JEE MAIN - Physics (2023 - 11th April Evening Shift - No. 11)
The logic operations performed by the given digital circuit is equivalent to:
_11th_April_Evening_Shift_en_11_1.png)
NOR
AND
NAND
OR
คำอธิบาย
_11th_April_Evening_Shift_en_11_2.png)
$$ \begin{aligned} Z =\overline{(A+B) \cdot(A \cdot B)} \\\\ Y =\bar{Z}=(A+B) \cdot(A \cdot B) \\\\ \end{aligned} $$
$$ Y=A \cdot(A B)+B \cdot(A B) $$
$$ \begin{aligned} & =A B+A B \\\\ & =(A B) \end{aligned} $$
$\therefore$ It is an AND gate.